Gate2017 cs Q60

60Let p, q, and r be propositions and the expression (p → q) → r be a contradiction. Then, the expression (r → p) → q is

Option : D
Explanation : (p → q) → r is contradiction only when
P q r
T T F
F T F
F F F
And now for the above combination, the expression is always true when q is true. When q is false in the above combination (third one) will be false.

Forgot your password?

I agree with the Terms.