EMNA Q.47

47A gardener had a number of shrubs to plant in horizontal rows. At first he tried to plant 5 shrubs in each row, then 6, then 8 and then 12, but had always 1 left. On trying 13, in one row he had none left. What is the smallest number of shrubs that he could have had?

Option : A
Explanation :
Number is 120K + 1= ((13 * 9 + 3) K + 1)
= 13 * 9K + 3 K + 1, which is divisible by 13.
3K + 1 is divisible by 13.
∴ K = 4. Number = 481

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