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Find the Output: Alternating digit positions

16Find the output of the following C code (assume #include <stdio.h> and that the code is inside int main(void)):
int n = 73142, sum = 0, position = 1;
while (n > 0) {
    int digit = n % 10;
    if (position % 2 == 0)
        sum += digit;
    else
        sum -= digit;
    position++;
    n /= 10;
}
printf("%d", sum);
  • Option : D
  • Explanation : Reading digits from right to left produces -2+4-1+3-7 = -3.