PREVIOUS YEAR SOLVED PAPERS MCQ - GATE 2020

Correct AnswerOption A
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Insertion of an element into AVL requires O(log n) time.
To insert an element
1. Find the position, where to insert
2. After insertion, to satisfy AVL properly, we may need to perform rotation.
So, (1) take ‘log n time’ and (2) take ‘log n’ time.
Total time for inserting one element into AVL tree is
log n + log n = 2 log n ⇒ O (log n).
Now, To insert n2 elements ⇒ n2 log n
⇒ O(n2 log n)
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Correct AnswerOption A
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w(u, v)=(u, v ) edge weight
w′(u, v) = w(u, v) + [f(u) - f(v)]/0 = w (u, v)
So, option (A) correct.
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Correct AnswerOption B
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Follow:

∀x (p(x) → W) ⇒ (∀x p(x)) → W is wrong
∀ x [(px) → W] ≡ ∀x [∼P(x) ∨ W]
≡ ∀x [∼P(x) ∨ W]
≡ ∼ [∃x p(x)] ∨ W)
≡ ∃x p(x)] → W
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Correct AnswerOption C
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z = a + bc
solving it with K-map

∴ Minterms will be
= ∑m(1, 4, 5, 6, 7)
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Correct AnswerOption C
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Word length = 32 bit, MM size = 16 MB
Physical address = 24 bit, CM size = 64 KB
4-way set associative
Block size = 256 B
Number of lines (N) = 64K/256 = 216/28 = 28
Number of sets (S) = N/P-way = 28/4 = 26
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