In Schema II : Registration (rollno, courseid,
email)
Non-trivial functional dependencies:
{ rollno, courseid → email
email → rollno }
candidate keys
{rollno, courseid,}
email courseid}
Given relation is in 3NF but not in BCNF.
PREVIOUS YEAR SOLVED PAPERS MCQ - GATE 2018
A = UVT
(1 - λ)(2 - λ) - 2 = 0
λ2 - 3λ = 0
λ(λ - 3) = 0
λ = 0
or, λ = 3
The largest eigen value is 3.Given,
Number of processes (P) = 3
Number of resources (R) = 4
Since deadlock-free condition is:
R ≥ P(N − 1) + 1
Where R is total number of resources,
P is the number of processes, and
N is the max need for each resource.
4 ≥ 3(N − 1) + 1
3 ≥ 3(N − 1)
1 ≥ (N − 1)
N ≤ 2
Therefore, the largest value of K that will always avoid deadlock is 2.
Option (A) is correct.
Given |G| = 84
Solutions:
By Lagrang’s theorem any subgroup size is a divisior of 84.
But a proper subgroup cannot have same size as group.
So largest divisor of 84, other than 84 is 42.
So, largest proper subgroup can have in size of 42.


