Discrete Maths - Propositional and first order logic
12. What can we correctly say about proposition P1:
P1 : (p v ˥q) ^ (q →r) v (r v p)
- Option : C
- Explanation :
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13. (P v Q) ^ (P → R )^ (Q →S) is equivalent to
- Option : C
- Explanation :
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14. The functionally complete set is
- Option : D
- Explanation :
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15. (P v Q) ^ (P→R) ^ (Q → R) is equivalent to
- Option : C
- Explanation :
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