Computer Networks MCQ - Computer Networks Section 3
In slow-start phase, for each ACK, the sender
increases the current transmit window by
Maximum Segment Size (MSS).
As per question, a packet consists of 2000 bytes and that can be taken as MSS. So, after two ACKs, current transmit window
= 4000 + 2000 + 2000
= 8000
As per question, a packet consists of 2000 bytes and that can be taken as MSS. So, after two ACKs, current transmit window
= 4000 + 2000 + 2000
= 8000

