CTET Solved Paper - UPTET Feburary 2014 Paper2

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121. The abscissa of the point (-2, -5) is

  • Option : B
  • Explanation : For point (x,y) x is the abscissa and y is the ordinate. Abscissa of (-2, -5) is -2.
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122. If the number 23583ab is completely divisible by 80, then the value of a - b is

  • Option : A
  • Explanation : 23583ab is divisible by 80, so it should be divisible by both 8 and 10 (factors of 80).
    For 23583ab to be divisible by 10,
    ∴ b = 0
    Now, by divisibility rule of 8,
    3ab, i.e. 3a0 must be divisible by 8.
    Only a = 2 makes it possible.
    ∴ a - b = 2.
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123. LCM and HCF of two numbers p and q are P and Q, respectively.
If P - p = q - Q, then

  • Option : A
  • Explanation : For two numbers p and q having LCM and HCF as P and Q respectively, we have pq = PQ
    Given, p - P = q - Q
    ⇒ p + q = P + Q
    Squaring on both sides, we get
    p2 + q2 + 2pq = P2 + Q2 + 2PQ
    ⇒ p2 + q2 = P2 + Q2 [as pq=PQ].
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124. A person have some one rupee, 50 paise and 25 paise coins totalling ₹210 in the ratio 5 : 6 : 8, then number of one rupee coin is

  • Option : D
  • Explanation : The ratio of the number of ₹1, 50 paise and 25 paise coins is 5 : 6 : 8.
    Therefore, the ratio of their contribution in ₹210 is
    = 5 : 6/2 : 8/2.
    i. e. 5 : 3 : 4.
    Contribution of ₹1 coins in ₹210
    = 5/(5 + 3 + 2) x 210.
    = 105
    ∴ Number of ₹1 coins = 105.
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125. If 3 ≤ x ≤ 10 and 5 ≤ y ≤ 15, then minimum value of (x/y) is

  • Option : C
  • Explanation : Minimum
    (x/y) = Minimum/ Maximum
    3/15 = 1/5.
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