Explanation : (A) Let the normal speed of the bus be 'x' km/h to cover the distance of 300 km in time 't' h.
∴ Distance = speed × time
⇒ 300 = x × t
If speed increased by 5 km/h, then
speed = (x + 5) km/h
and time = (t - 2)h
Then, distance = (x + 5) (t - 2)
⇒ 300 =(x + 5)(t - 2)
⇒ 300 = xt - 2x + 5t - 10
⇒ 2x2 + 10x - 1500 = 0
⇒ x2 + 5x - 750 = 0
⇒ x2 + 30x - 25x - 750 = 0
⇒ x(x + 30) - 25 (x + 30) = 0
⇒ (x - 25)(x + 30) = 0
⇒ x = 25, -30
Hence, normal speed of the bus is 25km/h
Explanation : (C) Area of three adjacent faces of a cuboid are in the ratio of 7: 10 : 14.
Let area of three faces be 7x, 10x, and 14x.
Let the length, breadth and height of cuboid be l, b and h, respectively.
Volume of cuboid = 350 cm3
⇒ l × b × h = 350 cm3 ........(i)
According to the figure,
l × b = 14x .........(ii)
l × h = 7x ..........(iii)
b × h = 10x ............(iv)
On multiplying (ii), (iii) and (iv)
l2b2h2 = (14x)(7x)(10x)
⇒ (lbh)2 = (14 × 7 × 10)x3
⇒ (350)2 = (980)x3
x3 = 125 ⇒ x = 5
Area of the faces are
7x = 7 × 5 = 35 = l × h
10x = 10 × 5 = 50 = b × h
14x = 14 × 5 = 70 = l × b
Put the value of l × h = 35 in Eq (i), then
l × b × h = 350
⇒ 35 × b = 350
⇒ b = 10 cm
Similarly,
l × b × h = 350
⇒ l × 50 = 350
⇒ l = 7 cm
and l × b × h = 350
⇒ 70 × h = 350
⇒ h = 5 cm
∴ Longest side has a length of 10 cm.