CTET Solved Paper - UPTET December 2016

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61. If the speed of a bus is increased by 5 km/h from its normal speed, it takes 2 hour less for a journey of 300 km, then the normal speed of bus (in km/h) is

  • Option : A
  • Explanation : (A) Let the normal speed of the bus be 'x' km/h to cover the distance of 300 km in time 't' h.
    ∴ Distance = speed × time
    ⇒ 300 = x × t

    If speed increased by 5 km/h, then
    speed = (x + 5) km/h
    and time = (t - 2)h
    Then, distance = (x + 5) (t - 2)
    ⇒ 300 =(x + 5)(t - 2)
    ⇒ 300 = xt - 2x + 5t - 10

    ⇒ 2x2 + 10x - 1500 = 0
    ⇒ x2 + 5x - 750 = 0
    ⇒ x2 + 30x - 25x - 750 = 0
    ⇒ x(x + 30) - 25 (x + 30) = 0
    ⇒ (x - 25)(x + 30) = 0
    ⇒ x = 25, -30
    Hence, normal speed of the bus is 25km/h
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62. If 92x-1 = 25 - 5, then value of x is

  • Option : D
  • Explanation : (D) 92x-1 = 25 - 5
    ⇒ 92x-1 = 32 - 5
    ⇒ 92x-1 = 27
    ⇒ 32(2x-1) = 33
    Powers of same base are equal.
    ∴ 2(2x - 1) = 3
    ⇒ 4x - 2 = 3
    ⇒ 4x = 5
    ⇒ x = 5/4
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63. The areas of three adjacent faces of a cuboid are in the ratio 7 : 10 : 14. If the volume of cuboid is 350cm3, then the longest side has a length of

  • Option : C
  • Explanation : (C) Area of three adjacent faces of a cuboid are in the ratio of 7: 10 : 14.
    Let area of three faces be 7x, 10x, and 14x.
    Let the length, breadth and height of cuboid be l, b and h, respectively.

    Volume of cuboid = 350 cm3
    ⇒ l × b × h = 350 cm3 ........(i)
    According to the figure,
    l × b = 14x .........(ii)
    l × h = 7x ..........(iii)
    b × h = 10x ............(iv)
    On multiplying (ii), (iii) and (iv)
    l2b2h2 = (14x)(7x)(10x)
    ⇒ (lbh)2 = (14 × 7 × 10)x3
    ⇒ (350)2 = (980)x3

    x3 = 125 ⇒ x = 5
    Area of the faces are
    7x = 7 × 5 = 35 = l × h
    10x = 10 × 5 = 50 = b × h
    14x = 14 × 5 = 70 = l × b
    Put the value of l × h = 35 in Eq (i), then
    l × b × h = 350
    ⇒ 35 × b = 350
    ⇒ b = 10 cm
    Similarly,
    l × b × h = 350
    ⇒ l × 50 = 350
    ⇒ l = 7 cm
    and l × b × h = 350
    ⇒ 70 × h = 350
    ⇒ h = 5 cm
    ∴ Longest side has a length of 10 cm.
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64. The sum of three consecutive multiples of 3 is 99. These multiples are

  • Option : C
  • Explanation : (C) Let the three consecutive multiples of 3 be 3x, 3x + 3, 3x + 6
    Then, according to the question,
    3x + 3x + 3 + 3x + 6 = 99
    ⇒ 9x + 9 = 99
    ⇒ 9(x + 1) = 99
    ⇒ x + 1 = 11
    ⇒ x = 11 - 1 = 10
    Thus, the three multiples are
    3x = 3 × 10 = 30
    3x + 3 = 3 × 10 + 3 = 33
    3x + 6 = 3 × 10 + 6 = 36
    Multiples of 3 are 30, 33, 36.
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65. Seema reads of a book per hour. If she goes to sleeping after reading the book for hours. How much part of book is now left to be read?

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