Quantitative Aptitude - Permutation And Combinations
- Option : A
- Explanation : 3 consonants out of 5 can be selected in 5C3 ways. 2 vowels out of 4 can be selected in 4C2 ways. Therefore, total number of groups each containing 3 consonants and 2 vowels = 5C3 * 4C2 = 5*6=30 Each group contains 5 letters, which can be arranging in 5! ways. Therefore required number of words = 30* 5! = 3600
- Option : A
- Explanation : Required number of ways are 45=1024. Since each prize can be distributed in 4 ways
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