Mathematics MCQ - Calculus

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Since the value of a mod function cannot be less than zero, therefore f(x) = | x2-5x+2 | is zero.

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Calculus
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Let f(x) = -x3 + 6x2 + 2x + 1

Slope of the function is,       f'(x)  =  -3x2 + 12x + 2 = F(x) (say) Now to find minimum or maximum of F(x) Therefore                  F'(x) = - 6x + 12 F"(2) = -6 For maxima and minima, F'(x) = 0 ⇒                                x = 2
Therefore                   F"(2) = -6
Hence F(x) (slope) is maximum at x = 2
  Maximum slope = F(2) = -3(2)2 + 12(2) + 2 = 14
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f ' (x) = 3(x2 - 4x + 3), f '' (x) = 6(x) - 12 At     x = 1, f "(1) At     x = 3, f " (3) = + ve
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