Since the value of a mod function cannot be less than zero, therefore f(x) = | x2-5x+2 | is zero.
Mathematics MCQ - Calculus
Let f(x) = -x3Â + 6x2Â + 2x + 1
Slope of the function is,    f'(x)  =  -3x2 + 12x + 2 = F(x) (say) Now to find minimum or maximum of F(x) Therefore          F'(x) = - 6x + 12 F"(2) = -6 For maxima and minima, F'(x) = 0 ⇒                 x = 2
Therefore          F"(2) = -6
Hence F(x) (slope) is maximum at x = 2
 Maximum slope = F(2) = -3(2)2 + 12(2) + 2 = 14
f ' (x) = 3(x2Â - 4x + 3), f '' (x) = 6(x) - 12
At   x = 1, f "(1)
At   x = 3, f " (3) = + ve



