Mathematics MCQ - Calculus

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f'(x)= x2-1 For maximum and minimum value, f'(x) = 0 ∴ x2 -1= 0  x = ± 1 Again f(x) = 2x  At x = 1, f '(x) = 2 > 0  f '(x) = -2 < 0 Hence minimum at x = 1
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Calculus
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