Correct hierarchical relationship among context free, rightlinear, and contextsensitive language is
A.  contextfree ⊂ rightlinear ⊂ contextsensitive 
B.  contextfree ⊂ contextsensitive ⊂ rightlinear 
C.  contextsensitive ⊂ rightinear ⊂contextfree 
D.  rightlinear ⊂contextfree ⊂contextsensitive 
Option: D Explanation : Click on Discuss to view users comments. 
In the following grammar :
x : : = x ⊕ y  4
y : : = z * y I 2
z : : = id
which of the folowing is true ?
A.  ⊕ is left associative while * is right associative 
B.  Both ⊕ and * are left associative 
C.  ⊕ is right associative while * is left associative 
D.  None of these 
Option: B Explanation : Click on Discuss to view users comments. Preeti said: (4:23am on Thursday 21st November 2013)
Answer A is correct.
anita said: (11:20pm on Tuesday 2nd May 2017)
ans a is correct
Ankit said: (11:42am on Thursday 24th August 2017)
A answer is correct

Which of the following CFG's can't be simulated by an FSM ?
A.  S > Sa  b 
B.  S > aSb  ab 
C.  S > abX, X > cY, Y > d  aX

D.  None of these 
Option: B Explanation : Option (b) generates the set {a^{n} b^{n} ,n=1,2,3 ....}which is not regular ,Option (a) is left linear where as option (C) is right linear . Click on Discuss to view users comments. 
ADG is said to be in Chomsky Form (CNF), if all the productions are of the form A > BC or
A > a. Let G be a CFG in CNF. To derive a string of terminals of length x , the number of productions to be used is
A.  2x  1 
B.  2x 
C.  2x + I 
D.  None of these 
Option: A Explanation : Click on Discuss to view users comments. kavita said: (11:11pm on Sunday 9th June 2013)
why option a?

Which of the following statements is correct?
A.  A = { If a^{n} b^{n}  n = 0,1, 2, 3 ..} is regular language 
B.  Set B of all strings of equal number of a's and b's deines a regular language 
C.  L (A* B*)∩ B gives the set A 
D.  None of these 
Option: C Explanation :
If we include A and B in a set and if we write A* it means except then A i.e. B same as B* means except then B i.e.A so if we intersect (A*B*) and B then get A because in any regular language
if we write AB then AB=A intersection B' so if we intersect A and B means AB So intersection of (A*B*) and B = (BA) intersection B means (BA)B' and B'=A so (BA) intersection(A)=A
So ans is (C)
Click on Discuss to view users comments. Abdul said: (9:46am on Wednesday 7th December 2016)
What if A does not contain the empty string?

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