Object Oriented Programming - Find Output
1. The following program fragment
int i=10;
void main ( )
{
int i=20;
{
int i=30.;
cout << i << :: i ;
}
}
- Option : A
- Explanation : :: is basically meant to manipulate a global variable, in case a local variable also has the same name.
3. The following c++ code results in
#include "iostream.h"
void main (void)
{
cout << (int i=5) << (int j=6);
}
4. The statements
int a = 5;
cout << "FIRST" << (a <<2) << "SECOND";
outputs
- Option : B
- Explanation : The symbol << has a context sensitive meaning. The << in (a << 2) means shifting a by 2 bits to the left, which is nothing but multiplying it by 4. So, a < <2 will be 5 x 4 = 20 and hence the output will be FIRST20SECOND.
5. The following program fragment
void main ( )
{
int x=10;
int &p=x;
cout << &p << &x;
}
- Option : D
- Explanation : int &p=x aliases p to x. This means they refer to the same memory location. So, the address of x will be same as that of p.
