uptetd16p1 q108

0. If 31x5 is a multiple of 9, where x is a digit, then the value of x will be

  • Option : D
  • Explanation : (D) By divisibility test, when the sum of all the digits of a number is divisible by 9, then the number is also divisible by 9.
    Thus 31x5 is a multiple of 9 only when the sum of all the digits of a number is divisible by 9
    ∴ 3 + 1 + x + 5 = 9 + x
    Hence, from the following given options, value of x - 9
    9 + x = 9 + 9 = 18
    and 18 is divisible by 9
    ∴ 195 is a multiple of 9 and x = 9
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