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0. 3 pipes can fill a reservoir in 10, 15 and 20 hours respectively. If the three taps are opened one after another in the given order, with a certain fixed time gap between them, the reservoir fills in 5 hours. The time gap will be.
hr
1 hr
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hr
hr
⇒ (5)6 + (5 - x)4 + (5 - 2x)3 = 60
⇒ 30 + 20 - 4x + 15 - 6x = 60
⇒ x =
hour.
⇒ (5)6 + (5 - x)4 + (5 - 2x)3 = 60
⇒ 30 + 20 - 4x + 15 - 6x = 60
⇒ x = hour.