STATISTICS AND METHODOLOGY QUESTION NO 52
- Option : C
- Explanation : N = 15, r = 0.6 Z = 1.1513 log 1 + r/1 - r = 1.1513 log 1 + 0.6/1 - 0.6 = 1.1513 log 4 = 1.1513 x 0.6021 = 0.6932 S.E.2 = 1/√(N - 3) = 1√(15 - 3) = 1√12 = 1/3.464 = 0.29 Z/(S.E.)2 = 0.6932/0.29 =2.39 > 1.96 Hence 'r' is significant at a 5% level of significance. The answer is (c).
