Q41
- Option : B
- Explanation : Let the ΔABC, in which AM and CN are angle bisectors.
∠A + ∠B + ∠C =180°
⇒ ∠A + 110° + ∠C = 180°
⇒ ∠A + ∠C=180-110°
⇒ ∠A/2 + ∠C/2 = 70°/2
⇒ ∠A/2 + ∠C/2 = 35 ... (i)
Now the angle bisectors meet at O.
In ΔAOC,
∠A/2 + ∠C/2 + ∠AOC =180°
=> 35° + ∠AOC = 180° [From Eq. (i)]
⇒ ∠AOC = 180° - 35°
∠AOC = 145°
