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0. H2S(g) + Cl2(g) → 2HCL(g) + S(s) The reaction is interpreted as (NTSE Delhi, Stage-I, 2012-13)
H2S is getting oxidized and Cl2 is getting reduced
H2S is getting reduced and Cl2 is getting oxidized
Only H2S is oxidized
Both H2S and Cl2 are reduced
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