PA of Algorithms Q38
- Option : C
- Explanation : Given program fragment in Pseudo language is
x = m ;
y = 1 ;
while (x – y > e)
x = (x + y) /2 ;
y = m/x ;
}
Print (x)
This program will find out the square root of m,
suppose that m = 2
as x – y = 0 exit from loop hence print 1.414 which is root of 2.X- Y X Y 1st looping 2 3/2=1.5 2/1.5=1.33 2nd looping .16 (1.5+1.3)/2 = 1.415 2.0/1.415 = 1.413 3rd looping 0.02 1.414 1.414 4th looping 0
