Explanation : f(n) = n2 logn
g(n) = n (logn)10
Here we can remove common factor from both the function to simply the value of f(n) & g(n)
So f(n) = n
g(n) = (logn)9
Now choose the largest value of n to compare both the function.
if n = 2100 then f(n) = 2100
g(n) = (100)9
f(n) > g(n).