Nov2017 cs Q49
0. Negation of the proposition ∃ x H(x) is: (1) ∃x ¬ H(x) (2) ∀x ¬ H(x) (3) ∀x H(x) (4) ¬ x H(x)
- Option : B
- Explanation : ince logic says that there exist some x for which H(x) is true, So the negation for this will be for all x H(x) is not true. We can write it: ¬∃xH(x) =∀x¬H(x) So, option (B) is correct.
