Memory Hierarchy Q.80

0. Consider a machine with a byte addressable main memory of 232 divided into blocks of size 32 bytes. Assume that a direct mapped cache having 512 cache lines is used with this machine. The size of the tag field in bits is ................ .

  • Option : A
  • Explanation : Total address space = 32 bit
    offset bit (B) = 5 bit
    No. of bit to represent line no (L) = 9.
    Tag bit + B + L = 32
    = X + 5 + 9 = 32
    = X = 18
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