July2016 cs Q37
| Process | Max.need | Allocation |
| P1 | 8 | 3 |
| P2 | 9 | 4 |
| P3 | 5 | 2 |
| P4 | 3 | 1 |
- Option : C
- Explanation : Current allocation of P1P2P3P4 are 3, 4, 2, 1 which is 10 in total. We have 12 total no of resources and out of them 10 are allocated so, we have only 2 resources. There is 5, 5, 3, 2 resources are needed for P1P2P3P4 respectively. So, P4 will run first and free 3 resources after execution. Which are sufficient for P3 So it will execute and do free 5 resources. Now P1 and P2 both require 5 resources each So we can execute any of them first but we will give priority to P1. The execution order will be P4P3P1P2. SO, option (C) is correct.
