Gate2020 cs Q64

0. Consider a TCP connection between a client and a server with the following specifications: the round trip time is 6 ms, the size of the receiver advert window is 50 KB, slow-start threshold at the client is 32 KB, and the maximum segment size is 2 KB. The connection is established at time t = Assume that there are no timeouts and errors during transmission. Then the size of the congestion window (in KB) at time t + 60 ms after all acknowledgments processed is _______.

  • Option : B
  • Explanation :
    TCP connections at t = 0
    1MSS = 2KB Threshold = 32KB (slow start)
    RTT = 6ms. Then how big packet it (packet size) may deliver after t + 60 ms
    Gate2020 cs
    1 RTT = 6 ms
    ⇒ 10 RTT = 60 ms
    t + 60 = 0 + 60 = 60 ms
    At 60 ms, CWND = 22 MSS
    1 MSS = 2KB
    ⇒ 22 MSS = 22 × 22 = 44 KB
Cancel reply

Your email address will not be published. Required fields are marked *


Cancel reply

Your email address will not be published. Required fields are marked *