Explanation : Given, total number of instructions (n) = 100
Number of stages (k) = 5
Since, if n instructions take c cycle, so (c-1) stalls will occur for these instructions.
Therefore, the number of clock cycles required = Total number of cycles required in general case + Extra cycles required (here, in PO stage)
= (n + k – 1) + Extra cycles
= (100 + 5 -1) + 40*(3-1)+35*(2-1)+20*(1-1)
= (100 + 4) + 40*2+35*1+20*0
= 104 + 115
= 219 cycles