Explanation : The given Grammar over Σ = {a, b, c} with S as the start symbol is
S → abScT | abcT
T→ bT | b
The minimum length string generated by the grammar is 1:
S→abcT→abcb; hence all variable greater than 1.
Other cases
S → abScT→ ab abScT cT → ab ab abScT cT cT →........→ (ab)n (cT)n.
Here T can generate any number of b’s starting with single b.
Hence The language is
{(abncbm1cbm2…cbmn | n, m1, m2, ….., mn ≥ 1 }