Explanation : The following data is given
File Size = 1000 bytes
Header Size = 100 bytes
Transmission Speed of all links = 10^6 bytes/sec
Case (1) :
Transmission time for one link
= packetsize/bandwidth
= (1000 + 100)/10^6
= 1100 microsecond.
So, Total time(T1) is 3*1100
= 3300 microsecond
Case (2) :
Transmission time for one link and one part
= (100 + 100)/10^6
= 200 microseccond
Note : While a packet is being transmitted from
R1 to R2, at the same time other packet is being
transmitted from A to R1.
So, Total time(T2) = 3 * 200 + 9 * 200
= 2400 microsecond
Case (3) :
Transmission time for one link and one part
= (50 + 100)/10^6
= 150 microsecond
Total time (T3) = 3 * 150 + 19 * 150
= 3300 microsecond
hence T1 = T3, T3 > T2