Functions of OSI and TCP/IP Layers Q.68

0. Host A sends a UDP datagram containing 8880 bytes of user data to host B over an Ethernet LAN. Ethernet frames may carry data up to 1500 bytes (i.e. MTU = 1500 bytes). Size of UDP header is 8 bytes and size of IP header is 20 bytes. There is no option field in IP header. How may total number of I P fragment s will be transmitted and what will be the contents of offset field in the last fragment?

Answer
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Option : C
Explanation : UDP data = 8880 bytes
UDP header = 8 bytes
IP Header = 20 bytes
Total Size(excluding IP Header) = 8888 bytes.
Number of fragments = 8888/1480 = 7
Offset of last segment = (1480 * 6)/8 = 1110

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