EMNA Q.14

0. HCF of y³ - 4y and 4y (y³ + 8) is

Answer
Comment
Array

Option : A
Explanation : y³-4y = y(y²-4)
= y(y-2)(y+2)
4y(y³+8)
=4y(y+2)(y²-2y+4)
∴ HCF = y(y + 2).

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