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0. A grammar to generate { (ab)n I n ≥ 1 } ∪ { (ba)n I n ≥ 1 } is constructed as
S ---> S1, S1 ---> abS1, S1 ---> ab, S ---> S2, S2 —> baS2, S2 —> ba
S ---> S1 , Sl ---> aS1, S1 ---> ab, S ---> S2, S2 ---> bS2, S2 —> bc
S —> S1, S1—>S2, S2 —> S1a, S1 —> ab, S2 —> ba
none of these
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