Explanation : 1 cycle time for p1 = 101/1GH = 1n.s. Assume p1 takes 5 cycles for a program then p2 takes 20% more, means, 6 cycles. p2 Takes 25% less time, means, if p1 takes 5 n.s, then p2 takes 3.75 n.s. Assume p2 clock frequency is x GHz. p2 taken 6 cycles, so 6*101/xGH = 3.75, x = 1.6