Explanation : It is given that transmission rate of a channel is 32 kbps and ‘8’ routes from source to destination and each packet p contains 8000 bits. Total delay = routes * packets / transmission rate. i.e. 8 * 8000 b / 32 kbps = 8 * 8000 b / 32000 bps = 2 s So, option (A) is correct.