ctets15p2 q52
0. The smallest value of y in the number 9y8071 so that it is divisible by 11 is
- Option : C
- Explanation : (C) We can solve this by using the divisibility rule of 11.
It states that when the sum of digits at odd and even places are equal or differ by a number divisible by 11, then the number is also divisible by 11.
For, 9y8071
Sum of digits at odd places = 9 + 8 + 7 = 24
Sum of digits at even places = y + 0 + 1 = y + 1
⇒ 24 - (y + 1) = 23 - y
∴ To make this number divisible by 11, we have to put the value of y as 1.
