CTET Feb16p2, q34

34ABCD is a quadrilateral in which BD = 40 cm. The lengths of the perpendiculars drawn from the opposite vertices on BD are 16 cm and 12 cm. The area of the quadrilateral (in cm²) is

Option : A
Explanation :
∴ Here, BD divides quadrilateral in two triangles.
Now,
Area of ΔABD = 1/2 x BD x AM
⇒ 1/2 x 40 x 16 = 320cm²
Area of ΔBCD = 1/2 x BD x NC
⇒ 1/2 x 40 x 16 = 240cm²
∴ Area of quadrilateral
ABCD = 320 + 240 = 560 cm².

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