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Find the Output: Postincrement in for condition

49Find the output of the following C code (assume #include <stdio.h> and that the code is inside int main(void)):
int i = 1, count = 0;
for (; i++ < 7;) {
    if (i % 2 == 0)
        count += i;
}
printf("%d %d", count, i);
  • Option : A
  • Explanation : The body sees i=2 through 7. Even values 2,4,6 contribute 12; the failed condition increments i to 8.