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14Find the output of the following C code (assume #include <stdio.h> and that the code is inside int main(void)):
int i, j, sum = 0;
for (i = 1; i <= 3; i++) {
    for (j = 1; j <= 4; j++) {
        if ((i + j) % 2 == 0)
            continue;
        sum += i * j;
    }
}
printf("%d", sum);
  • Option : C
  • Explanation : Only odd i+j pairs contribute: 6 for i=1, 8 for i=2, and 18 for i=3, totaling 32.