Explanation : Using concept of power of cycle:
(A) (0,1,4,9,6,5,6,9,4,1,0) repeated
(B) (0,1,4,9,6,5,6,9,4,1,0) repeated
(C) (0,1,8,7,4,5,6,3,2,9) repeated
(D) (0,2,4,6,8) repeated
So, only h(i) =i3 mod 10 covers all the digits from 0 to 9.
Option (C) is correct.