DT Q47

  • Option : C
  • Explanation :
    The problem can be solved using matrix chain multiplication. we get minimum number of multiplication using ((M1 × M2 ) × M3 ) × M4 )
    = 100 × 20 × 5 + 10 × 100 × 5 + 10 × 5 × 80
    = 19000.
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