Graph Algorithm 12

  • Option : D
  • Explanation :

    Suppose v is starting vertex so start DFS at node v
    (i) visit t (v) → DFS(A) → visit (A) → DFS (v) → visit (u) → back track (A) → Back track (v)
    therefore d[v] > d[v], d[v] < f[v] f[v] < f[v]
    But visiting order is just opposite of finishing order.
    Hence f[v] > f[v]
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