Functions of OSI and TCP/IP Layers Q.55

0. Suppose that the maximum transmit window size for a TCP connection is 12000 bytes. Each packet consists of 2000 bytes. At some point of time, the connection is in slow-start phase with a current transmit window of 4000 bytes. Subsequently, the transmitter receives two acknowledgement. Assume that no packets are lost and there are no time-outs. What is the maximum possible value of the current transmit window?

Answer
Comment
Array

Option : B
Explanation : In slow-start phase, for each ACK, the sender increases the current transmit window by Maximum Segment Size (MSS).
As per question, a packet consists of 2000 bytes and that can be taken as MSS. So, after two ACKs, current transmit window
= 4000 + 2000 + 2000
= 8000

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