Explanation : Consider optimum packet size which required
minimum number of packet and does not waste
any space.
Here consider each packet header because they
are all work on packet switching network.
3 bytes is header size;
9 – 3 = 6 is data size
24/6 = 4 are the required packet
For case 1 : 24 packets are required
For case 2 : 8 packets are required
For case 3 : 6 packets are required