Functions of OSI and TCP/IP Layers Q.31

0. In the network 200.10.11.144/27, the fourth octet (in decimal) of the last IP address of the network which can be assigned to a host is________.

  • Option : A
  • Explanation : Fourth octet of network address is 144 i.e. 10010000.
    The first three bits of this octal is subnet bit (100), remaining bits can get maximum value as 11111.
    So the maximum possible last octal IP address is 10011111 which is 159.
    But the address with all 1s in host part is broadcast address and can't be assigned to a host. So the maximum possible host is 158.
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