Functions of OSI and TCP/IP Layers Q.9

  • Option : D
  • Explanation : The following data is given
    File Size = 1000 bytes
    Header Size = 100 bytes
    Transmission Speed of all links = 10^6 bytes/sec
    Case (1) :
    Transmission time for one link
    = packetsize/bandwidth
    = (1000 + 100)/10^6
    = 1100 microsecond.
    So, Total time(T1) is 3*1100
    = 3300 microsecond
    Case (2) :
    Transmission time for one link and one part
    = (100 + 100)/10^6
    = 200 microseccond
    Note : While a packet is being transmitted from R1 to R2, at the same time other packet is being transmitted from A to R1.
    So, Total time(T2) = 3 * 200 + 9 * 200
    = 2400 microsecond
    Case (3) :
    Transmission time for one link and one part
    = (50 + 100)/10^6
    = 150 microsecond
    Total time (T3) = 3 * 150 + 19 * 150
    = 3300 microsecond
    hence T1 = T3, T3 > T2
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