Gate2020 cs Q49
is an number is _______ .
- Option : A
- Explanation : Let n = 3
0 ϵ < 0,1]3
x = 0 or 1
= x1 = x3 (∵ a1 = 1, a2= 0, a3 = 1)
= 0 or 1 or 1 or 2.
= x3 (∵ a1 = a2 = 0)
= 0 or 1
Total number of cases = 2 × 3 + 4 × 3 = 18
Now odd number of cases = 9
P = 9/18 = 0.5
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