Gate2018 cs Q60

0. Consider the following C program:
#include
void fun 1 (char *s1, char *s2) {
char *tmp;
tmp = s1;
s1 = s2;
s2 = tmp;
}
Void fun2 (char **s1, char **s2) {
char *tmp;
tmp = s1;
s1 = s2;
s2 = tmp;
}
int main () {
char *str1 = “Hi”, *str2 = “Bye”;
fun1 (str1, str2);
printf(“%s %s”, str1, str2);
fun2 (&str1, &str2);
printf(“%s %s”, str1, str2);
return 0;
}
The output of the program above is

Answer
Comment
Array

Option : A
Explanation :
fun1(char *s1, char *s2)
function scope is local, so the value changed So the affect actual parameters. SO the values will be ‘Hi Bye’.
fun2(char **s1, char **s2)
In this function value is pointer to pointer, so it changes pointer of the actual value. So values will be ‘Bye Hi’

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