Gate2018 cs Q3

0. What would be the smallest natural number which when divided either by 20 or by 42 or by 76 leaves a remainder of 7 in each case?

Answer
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Option : C
Explanation :
From the given number is divided by either by 20 or 42 or by 76 K*LCM (20,42,76) + constant difference = 7980 K + 7 is natural number . So the Ans is 7987

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