Explanation : (a) What is the maximum number of cells possible in the base cuboid?
pn.
This is the maximum number of distinct tuples that you can form with p distinct values
per dimensions.
(b) What is the minimum number of cells possible in the base cuboid?
p.
You need at least p tuples to contain p distinct values per dimension. In this case no
tuple shares any value on any dimension.
(c) What is the minimum number of cells possible in the data cube, C?
(2n-1)×p+1.
The minimum number of cells is when each cuboid contains only p cells, except for the
apex, which contains a single cell.
(d) What is the maximum number of cells possible (including both base cells and
aggregate cells) in the data cube, C?
(p+1)n.
The argument is similar to that of part (a), but now we have p+1 because in addition to
the p distinct values of each dimension we can also choose ∗.