EMSTAS Q.57
0. Let f : R → R be defined by
f(x)= {x+2 (x ≤ -1)
{ x2 (-1 ≤ x ≤1)
{2 - x (x ≥ 1)
Then value of f (-1.75) + f (0.5) + f (1.5) is
0. Let f : R → R be defined by
f(x)= {x+2 (x ≤ -1)
{ x2 (-1 ≤ x ≤1)
{2 - x (x ≥ 1)
Then value of f (-1.75) + f (0.5) + f (1.5) is
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