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0. What is the least number which on being divided by 5, 6, 8, 9, 12 leaves in each case a remainder 1 but when divided by 13 leaves no remainder?
2987
3601
3600
2986
L.C.M. of 5, 6, 8, 9 and 12 is 360Required number = 360 K + 1 = (13 x 27 + 9) K + 1= (13 x 27) K + (9K + 1)Now this number must be divisible by 13 K = 10 and required number = 3601.
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